36x^2-396x+720=0

Solution for 36x^2-396x+720=0 equation:

36x^2-396x+720=0

a = 36; b = -396; c = +720;
Δ = b2-4ac
Δ = -3962-4·36·720
Δ = 53136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{53136}=\sqrt{1296*41}=\sqrt{1296}*\sqrt{41}=36\sqrt{41}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-396)-36\sqrt{41}}{2*36}=\frac{396-36\sqrt{41}}{72}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-396)+36\sqrt{41}}{2*36}=\frac{396+36\sqrt{41}}{72}
$